Basic oracle queries Part -2

Part1 – Continue

81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.

SQL>select distinct(job) from emp where deptno=10 or deptno=20;

(or)

SQL>select distinct(job) from emp where deptno in(10,20);


82) Display the jobs which are unique to department 10.

SQL>select distinct(job) from emp where deptno=10;


83) Display the details of those who do not have any person working under them.

SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by e.ename having count(*)=1;


84) Display the details of those employees who are in sales department and grade is 3.

SQL>select * from emp where deptno=(select deptno from dept where dname=’SALES’)and sal between(select losal from salgrade where grade=3)and (select hisal from salgrade where grade=3);


85) Display those who are not managers and who are managers any one.

i)display the managers names

SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;

ii)display the who are not managers

SQL>select ename from emp where ename not in(select distinct(m.ename) from emp e,emp m where m.empno=e.mgr);


86) Display those employee whose name contains not less than 4 characters.

SQL>select ename from emp where length(ename)>4;


87) Display those department whose name start with “S” while the location name ends with “K”.

SQL>select dname from dept where dname like ‘S%’ and loc like ‘%K’;


88) Display those employees whose manager name is akash.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and e.ename=’Akash’;


89) Display those employees whose salary is more than 3000 after giving 20% increment.

SQL>select ename,sal from emp where (sal+sal*.2)>3000;


90) Display all employees while their dept names;

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno;


91) Display ename who are working in sales dept.

SQL>select ename from emp where deptno=(select deptno from dept where dname=’SALES’);


92) Display employee name,deptname,salary and comm for those sal in between 2000 to 5000 while location is Ahmedabad .

SQL>select ename,dname,sal,comm from emp,dept where sal  between 2000 and 5000 and loc=’AHMEDABAD’ and emp.deptno=dept.deptno;


93)Display those employees whose salary greter than his manager salary.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.sal>e.sal;


94) Display those employees who are working in the same dept where his manager is work.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.deptno=e.deptno;


95) Display those employees who are not working under any manager.

SQL>select ename from emp where mgr is null;


96) Display grade and employees name for the dept no 10 or 30 but grade is not 4 while joined the company before 31-dec-82.

SQL>select ename,grade from emp,salgrade where sal between losal and hisal and deptno     in(10,30) and grade<>4 and hiredate<’31-DEC-82′;


97) Update the salary of each employee by 10% increment who are not eligiblw for commission.

SQL>update emp set sal=sal+sal*10/100 where comm is null;


98) SELECT those employee who joined the company before 31-dec-82 while their dept location is newyork or  Chicago.

SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPT WHERE (EMP.DEPTNO=DEPT.DEPTNO)AND HIREDATE <’31-DEC-82′ AND DEPT.LOC IN(‘CHICAGO’,’NEW YORK’);


99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKING AS  MANAGER?

SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where mgr is not null;


100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS AKKI? —[AND ALSO DISPLAY THEIR MANAGER NAME]?

SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND E.ENAME=’AKKI’;


101) Display name and salary of ford if his salary is equal to hisal of his grade

SQL>select ename,sal,grade from emp,salgrade where sal between losal and hisal and ename =’FORD’ AND HISAL=SAL;


102) Display employee name,job,depart name ,manager name,his grade and make out an under department wise?

SQL>SELECT E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM EMP,EMP E,SALGRADE,DEPT WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME;


103) List out all employees name,job,salary,grade and depart name for every one in the company  except ‘CLERK’.Sort on salary display the highest salary?

SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT WHERE SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND JOB NOT IN(‘CLERK’)ORDER BY SAL ASC;


104) Display the employee name,job and his manager.Display also employee who are without manager?

SQL>select e.ename,e.job,eMP.ename AS Manager from emp,emp e where emp.empno(+)=e.mgr;


105) Find out the top 5 earners of company?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL>=E.SAL)ORDER BY SAL DESC;


106) Display name of those employee who are getting the highest salary?

SQL>select ename from emp where sal=(select max(sal) from emp);


107) Display those employee whose salary is equal to average of maximum and minimum?

SQL>select ename from emp where sal=(select max(sal)+min(sal)/2 from emp);


108) Select count of employee in each department  where count greater than 3?

SQL>select count(*) from emp group by deptno having count(deptno)>3;


109) Display dname where at least 3 are working and display only department name?

SQL>select distinct d.dname from dept d,emp e where d.deptno=e.deptno and 3>any (select count(deptno) from emp group by deptno);


110) Display name of those managers name whose salary is more than average salary of his company?

SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E WHERE EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);


111)Display those managers name whose salary is more than average salary of his employee?

SQL>SELECT DISTINCT EMP.ENAME FROM EMP,EMP E WHERE

E.SAL <(SELECT AVG(EMP.SAL) FROM EMP

WHERE EMP.EMPNO=E.MGR GROUP BY EMP.ENAME) AND

EMP.EMPNO=E.MGR;


112) Display employee name,sal,comm and net pay for those employee whose net pay is greter than or equal to any other employee salary of the company?

SQL>select ename,sal,comm,sal+nvl(comm,0) as NetPay from emp where sal+nvl(comm,0) >any (select sal from emp);


113) Display all employees names with total sal of company with each employee name?

SQL>SELECT ENAME,(SELECT SUM(SAL)  FROM EMP) FROM EMP;


114) Find out last 5(least)earners of the company.?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE

5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL<=E.SAL)

ORDER BY SAL DESC;


115) Find out the number of employees whose salary is greater than their manager salary?

SQL>SELECT E.ENAME FROM EMP ,EMP E WHERE EMP.EMPNO=E.MGR AND EMP.SAL<E.SAL;


116) Display those department where no employee working?

SQL>select dname from emp,dept where emp.deptno not in(emp.deptno);


117) Display those employee whose salary is ODD value?

SQL>select * from emp where sal<0;


118) Display those employee whose salary contains alleast 3 digits?

SQL>select * from emp where length(sal)>=3;


119) Display those employee who joined in the company in the month of Dec?

SQL>select ename from emp where to_char(hiredate,’MON’)=’DEC’;


120) Display those employees whose name contains “A”?

SQL>select ename from emp where instr(ename,’A’)>0;

or

SQL>select ename from emp where ename like(‘%A%’);


121) Display those employee whose deptno is available in salary?

SQL>select emp.ename from emp, emp e where emp.sal=e.deptno;


122) Display those employee whose first 2 characters from hiredate -last 2 characters of salary?

SQL>select ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2) from emp;


123) Display those employee whose 10% of salary is equal to the year of joining?

SQL>select ename from emp where to_char(hiredate,’YY’)=sal*0.1;


124) Display those employee who are working in sales or research?

SQL>SELECT ENAME FROM EMP WHERE DEPTNO IN(SELECT DEPTNO FROM DEPT WHERE DNAME IN(‘SALES’,’RESEARCH’));


125) Display the grade of Akki?

SQL>SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE SAL BETWEEN LOSAL AND HISAL AND Ename=’Akki’;


126) Display those employees who joined the company before 15 of the month?

SQL>select ename from emp where to_char(hiredate,’DD’)<15;


127) Display those employee who has joined before 15th of the month.

SQL>select ename from emp where to_char(hiredate,’DD’)<15;


128) Delete those records where no of employees in a particular department is less than 3.

SQL>delete from emp where deptno=(select deptno from emp group by deptno having count(deptno)<3);


129) Display the name of the department where no employee working.

SQL> SELECT E.ENAME,E.JOB,M.ENAME,M.JOB FROM EMP E,EMP M WHERE E.MGR=M.EMPNO;


130) Display those employees who are working as manager.

SQL>SELECT M.ENAME MANAGER FROM EMP M ,EMP E WHERE E.MGR=M.EMPNO GROUP BY M.ENAME;


131) Display those employees whose grade is equal to any number of sal but not equal to first number of sal?

SQL> SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE GRADE NOT IN(SELECT SUBSTR(SAL,0,1)FROM EMP);


132) Print the details of all the employees who are Sub-ordinate to BLAKE?

SQL>select emp.ename from emp, emp e where emp.mgr=e.empno and e.ename=’BLAKE’;


133) Display employee name and his salary whose salary is greater than highest average of department number?

SQL>SELECT SAL FROM EMP WHERE SAL>(SELECT MAX(AVG(SAL)) FROM EMP GROUP BY DEPTNO);


134) Display the 10th record of emp table(without using rowid)

SQL>SELECT * FROM EMP WHERE ROWNUM<11 MINUS SELECT * FROM EMP WHERE ROWNUM<10;


135) Display the half of the ename’s in upper case and remaining lowercase?

SQL>SELECT SUBSTR(LOWER(ENAME),1,3)||SUBSTR(UPPER(ENAME),3,LENGTH(ENAME)) FROM EMP;


136) Display the 10th record of emp table without using group by and rowid?

SQL>SELECT * FROM EMP WHERE ROWNUM<11 MINUS SELECT * FROM EMP WHERE ROWNUM<10;


137) Create a copy of emp table;

SQL>create table new_table as select * from emp where 1=2;


138) Select ename if ename exists more than once.

SQL>select ename  from emp e group by ename having count(*)>1;


139) Display all enames in reverse order?(SMITH:HTIMS).

SQL>SELECT REVERSE(ENAME)FROM EMP;


140) Display those employee whose joining of month and grade is equal.

SQL>SELECT ENAME FROM EMP WHERE SAL BETWEEN

(SELECT LOSAL FROM SALGRADE WHERE

GRADE=TO_CHAR(HIREDATE,’MM’)) AND

(SELECT HISAL FROM SALGRADE WHERE

GRADE=TO_CHAR(HIREDATE,’MM’));


141) Display those employee whose joining DATE is available in deptno.

SQL>SELECT ENAME FROM EMP WHERE TO_CHAR(HIREDATE,’DD’)=DEPTNO;


142) Display those employees name as follows

A ALLEN

B BLAKE

SQL> SELECT SUBSTR(ENAME,1,1),ENAME FROM EMP;


143) List out the employees ename,sal,PF(20% OF SAL) from emp;

SQL>SELECT ENAME,SAL,SAL*.2 AS PF FROM EMP;


144) Create table emp with only one column empno;

SQL>Create table emp as select empno from emp where 1=2;


145) Add this column to emp table ename vrachar2(20).

SQL>alter table emp add(ename varchar2(20));


146) Oops I forgot give the primary key constraint.  Add in now.

SQL>alter table emp add primary key(empno);


147) Now increase the length of ename column to 30 characters.

SQL>alter table emp modify(ename varchar2(30));


148) Add salary column to emp table.

SQL>alter table emp add(sal number(10));


149) I want to give a validation saying that salary cannot be greater 10,000 (note give a name to this constraint)

SQL>alter table emp add constraint chk_001 check(sal<=10000);


150) For the time being I have decided that I will not impose this validation.My boss has agreed to pay more than 10,000.

SQL>again alter the table or drop constraint with  alter table emp drop constraint chk_001 (or)Disable the constraint by using  alter table emp modify constraint chk_001 disable;


151) My boss has changed his mind.  Now he doesn’t want to pay more than 10,000.so revoke that salary constraint.

SQL>alter table emp modify constraint chk_001 enable;


152) Add column called as mgr to your emp table;

SQL>alter table emp add(mgr number(5));


153) Oh! This column should be related to empno.  Give a command to add this constraint.

SQL>ALTER TABLE EMP ADD CONSTRAINT MGR_DEPT FOREIGN KEY(MGR) REFERENCES EMP(EMPNO);


154) Add deptno column to your emp table;

SQL>alter table emp add(deptno number(5));


155) This deptno column should be related to deptno column of dept table;

SQL>alter table emp add constraint dept_001 foreign key(deptno) reference dept(deptno) [deptno should be primary key];


156) Give the command to add the constraint.

SQL>alter table <table_name) add constraint <constraint_name> <constraint type>;


157) Create table called as newemp.  Using single command create this table as well as get data into this table(use create table as);

SQL>create table newemp as select * from emp;

SQL>Create table called as newemp.  This table should contain only

empno,ename,dname.

SQL>create table newemp as select empno,ename,dname from emp,dept where

1=2;


158) Delete the rows of employees who are working in the company for more than 2 years.

SQL>delete from emp where (sysdate-hiredate)/365>2;


159) Provide a commission(10% Comm Of Sal) to employees who are not earning any commission.

SQL>select sal*0.1 from emp where comm is null;


160) If any employee has commission his commission should be incremented by 10% of his salary.

SQL>update emp set comm=sal*.1 where comm is not null;


161) Display employee name and department name for each employee.

SQL>select empno,dname from emp,dept where emp.deptno=dept.deptno;


162)Display employee number,name and location of the department in which he is working.

SQL>select empno,ename,loc,dname from emp,dept where emp.deptno=dept.deptno;


163) Display ename,dname even if there are no employees working in a particular department(use outer join).

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno(+);


164) Display employee name and his manager name.

SQL>select p.ename,e.ename from emp e,emp p where e.empno=p.mgr;


165) Display the department name and total number of employees in each department.

SQL>select dname,count(ename) from emp,dept where emp.deptno=dept.deptno group by dname;


166)Display the department name along with total salary in each department.

SQL>select dname,sum(sal) from emp,dept where emp.deptno=dept.deptno group by dname;


167) Display itemname and total sales amount for each item.

SQL>select itemname,sum(amount) from item group by itemname;


168) Write a Query To Delete The Repeted Rows from emp table;

SQL>Delete from emp where rowid not in(select min(rowid)from emp group by ename);


169) TO DISPLAY 5 TO 7 ROWS FROM A TABLE

SQL>select ename from emp where rowid in(select rowid from emp where rownum<=7 minus select rowid from empi where rownum<5);


170)  DISPLAY  TOP N ROWS FROM TABLE?

SQL>SELECT * FROM

(SELECT *  FROM EMP ORDER BY ENAME DESC)

WHERE ROWNUM <10;


171) DISPLAY   TOP 3 SALARIES FROM EMP;

SQL>SELECT SAL FROM ( SELECT  * FROM EMP ORDER  BY SAL DESC ) WHERE ROWNUM <4;


172) DISPLAY  9th FROM THE EMP TABLE?

SQL>SELECT ENAME FROM EMP

WHERE ROWID=(SELECT ROWID FROM EMP WHERE ROWNUM<=10

MINUS

SELECT ROWID FROM EMP WHERE ROWNUM <10);


select second max salary from emp;

select max(sal) fromemp where sal<(select  max(sal) from emp);


173) Delete the 10th record of emp table.

SQL>DELETE FROM EMP WHERE EMPNO=(SELECT EMPNO FROM EMP WHERE ROWNUM<11 MINUS

SELECT EMPNO FROM EMP WHERE ROWNUM<10);


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5 Comments

  1. find the employee whose sal lessthan his manager sal and more than other managers?
    send me reply..plz

  2. Hi
    I have a query. Pls solve this query
    count the employee_id within salary range like 5000 to 6000 and 6001 to 7000 and 7001 to 8000. this range of salary and also count employee_id. means How many employees earns with this salary range. Pls sove this. i am waiting for ur revert mail.

  3. Hi!i want 2 know this query answer,
    1.write a query to display avg sal of each employee.
    2.write a query to display max sal jobvice.
    3.write a query to display experience ofeach employee yearwise,monthwise,daywise.
    4.display no of characters of ename from emp table.
    plz send me these answers

  4. Haribrata Nayak September 28, 2011

    Hi Ruchi,
    Execute and see the result,hope u will get it from the below query

    select count(*) no_emp
    ,(select count(1) from emp where sal between 5000 and 6000 and
    deptno=t1.deptno) btw_5000_6000
    ,(select count(1) from emp where sal between 6001 and 7000 and
    deptno=t1.deptno) btw_6001_7000
    ,(select count(1) from emp where sal between 7001 and 8000 and
    deptno=t1.deptno) btw_7001_8000
    from emp t1 group by deptno

    exepected output
    ================
    no_emp btw_5000_6000 btw_6001_7000 btw_7001_8000
    ===========================================================
    30 12 15 3

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